/*Write a program to find whether given no. is Armstrong or not.
Example :
Input - 153
Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */
class Armstrong{
public static void main(String args[]){
int num = Integer.parseInt(args[0]);
int n = num; //use to check at last time
int check=0,remainder;
while(num > 0){
remainder = num % 10;
check = check + (int)Math.pow(remainder,3);
num = num / 10;
}
if(check == n)
System.out.println(n+" is an Armstrong Number");
else
System.out.println(n+" is not a Armstrong Number");
}
}
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2 comments:
error :Array index out of bounds exception
Hello Prasanth, we have to enter a value at run time. We used an instruction "int num = Integer.parseInt(args[0])" this line would take the first run time value as args[0]. So if you did not enter any value at execution, it generates an array index out of bounds exception. So follow the below syntax.
Ex: java Armstrong 153
java Armstrong 231
If you have any doubts can ask.
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